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6 Cards in this Set

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Formula to find out the capacitance when we know the pd across the capacitor and the charge stored :

C=Q/V

Is the charge stored on a capacitor proportional to the pd across the capacitor?

Yes

How to find out the energy transferred just as the charge crosses the main supply?

W =Q×V

How to find out the energy stores in the capacitor?

W=1/2 ×Q× V


W=1/2× C × V^2


W=Q^2/ 2C

Capacitors in parallel-

• the pd across each capacitor is same


• the total charge is the sum of the charge on individual capacitors


• the total capacitance is the sum of the two capacitances, C=C1 + C2

Capacitors in series:

• the charge on each capacitor is the same


• the pd is shared between the two capacitors


• the combined capacitance is 1/C= 1/C1 +1/C2